SOLUTION: The smaller of two consecutive even intigers is one less than half of the greater.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The smaller of two consecutive even intigers is one less than half of the greater.      Log On


   



Question 105677: The smaller of two consecutive even intigers is one less than half of the greater.
Found 2 solutions by elima, drsnyder66:
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
The smaller of two consecutive even integers is one less than half of the greater.
x = first integer
since they are even consecutive, they are 2 numbers apart;
x+2 = second integer
=================================
x-1=%281%2F2%29%28x%2B2%29
x-1=%281%2F2%29x%2B1
x-%281%2F2%29x=2
1/2x=2
x=4
========================
first integer = 4
second integer = 6
:)

Answer by drsnyder66(1) About Me  (Show Source):
You can put this solution on YOUR website!
For this problem we will represent the larger number as x.
Therefore the smaller number is x-2.
x-2+=+1%2F2+x+-+1
add 2 to both sides
x+=+1%2F2+x+%2B1
multiply 2 to both sides
2x+=+2%281%2F2x+%2B+1%29
2x+=+x%2B2
subtract x from both sides
x+=+2
therefore the numbers are 0 & 2
If you take 1/2 of 2, you get 1. 1 less than 1 is 0.
0 and 2 are 2 consecutive even numbers.

The previous answer does is not correct as it does not solve the problem.
if you take 1/2 of 6 you get 3, 1 less than 3 is 2. 2 & 6 are not two consecutive even numbers.