SOLUTION: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest doll
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Question 1056635: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest dollar, was invested in each? Found 2 solutions by jorel555, MathTherapy:Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let n be the amount invested at 7.6%. Then:
.076n=.059(5200-n)
.017n=306.8
n=1804.70
$1804.70 was invested at 7.6%; $3395.30 was invested at 5.9%. ☺☺☺☺
You can put this solution on YOUR website!
A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest dollar, was invested in each?
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