SOLUTION: Hooke’s law states that the distance D a spring stretches varies directly with the weight W attached to the spring. When a weight of 40 pounds is attached, the spring stretches 5

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hooke’s law states that the distance D a spring stretches varies directly with the weight W attached to the spring. When a weight of 40 pounds is attached, the spring stretches 5       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1056614: Hooke’s law states that the distance D a spring stretches varies directly with the weight W
attached to the spring. When a weight of 40 pounds is attached, the spring stretches 5 inches.
a. Express the distance that a spring stretches as a function of the weight attached.
b. Find the distance that the spring stretches from a 65 pound weight attached.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Hooke’s law states that the distance D a spring stretches varies directly with the weight W attached to the spring.
When a weight of 40 pounds is attached, the spring stretches 5 inches.
a. Express the distance that a spring stretches as a function of the weight attached.
D(w) = k*w
5 = k*40
k = 1/8
---
D(w) = (1/8)w
---------------------
b. Find the distance that the spring stretches from a 65 pound weight attached.
D(65) = (1/8)65 = 8.125 inches
-------------
Cheers,
Stan H.
------------