SOLUTION: A dog trainer has 92 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 408 ft2, what will be the dimensions of
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-> SOLUTION: A dog trainer has 92 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 408 ft2, what will be the dimensions of
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Question 1056445: A dog trainer has 92 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 408 ft2, what will be the dimensions of the work area? Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A dog trainer has 92 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 408 ft2, what will be the dimensions of the work area?
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P = 2W + 2L = 92
W + L = 46
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Area = W*L = 408
408 = 2*2*2*3*17
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Find a pair of factors of 408 with a sum of 46.
Hint: they're integers.
You can put this solution on YOUR website! .
A dog trainer has 92 ft of fencing that will be used to create a rectangular work area for dogs.
If the trainer wants to enclose an area of 408 ft2, what will be the dimensions of the work area?
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L + W = ====> L + w = 46.
L = 46-W,
W*L = 408 ---> W*(46-W) = 408,
W^2 -46W + 408 = 0,
= = = .
The only positive root is 34.
Answer. The dimensions are 34 ft and 46-34 = 12 ft.
The length is 34 ft, the width is 12 ft.
