SOLUTION: Systems with three variables (couldn't find the right category sorry)
Solve using elimination:
X+2y=2
2x+3y-z=-9
4x+2y+5z=1
I just need to know how to start it really. TIA
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Systems-of-equations
-> SOLUTION: Systems with three variables (couldn't find the right category sorry)
Solve using elimination:
X+2y=2
2x+3y-z=-9
4x+2y+5z=1
I just need to know how to start it really. TIA
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Question 1056369: Systems with three variables (couldn't find the right category sorry)
Solve using elimination:
X+2y=2
2x+3y-z=-9
4x+2y+5z=1
I just need to know how to start it really. TIA! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Solve using elimination:
X+2y=2
2x+3y-z=-9
4x+2y+5z=1
-----
Since the 1st eqn has no z term, eliminate that 1st.
10x+15y-5z=-45 -- 2nd eqn times 5
4x +2y + 5z =1
------------------------ Add
14x + 17y = -44
