SOLUTION: Find the vertex, axis of symmetry, x and y intercepts, y min or y max, domain and range then graph. y=2x2^-9x+7 Y intercept: set x=0 2(0)2^-9(0)+7 = 7 ??????

Algebra ->  Linear-equations -> SOLUTION: Find the vertex, axis of symmetry, x and y intercepts, y min or y max, domain and range then graph. y=2x2^-9x+7 Y intercept: set x=0 2(0)2^-9(0)+7 = 7 ??????      Log On


   

Question 1056263: Find the vertex, axis of symmetry, x and y intercepts, y min or y max, domain and range then graph.
y=2x2^-9x+7



Y intercept: set x=0 2(0)2^-9(0)+7 = 7 ??????
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Yes, the y-intercept is (0,7).
Complete the square and convert to vertex form,
y=2x%5E2-9x%2B7
y=2%28x%5E2-%289%2F2%29x%29%2B7
y=2%28x%5E2-%289%2F2%29x%2B%289%2F4%29%5E2%29%2B7-2%289%2F4%29%5E2
y=2%28x-9%2F4%29%5E2%2B7-81%2F8
y=2%28x-9%2F4%29%5E2%2B%2856-81%29%2F8
y=2%28x-9%2F4%29%5E2-25%2F8
So the vertex is (9%2F4,-25%2F8),
axis of symmetry is x=9%2F4,
Since 2%3E0, the parabola opens upwards so the vertex value is the minimum,
y%5Bmin%5D=-25%2F8.
Domain is all reals.
Range is [-25%2F8,infinity).
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