SOLUTION: A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the rectangle is 63 square feet. Find the length of the rectangle. Feet =

Algebra ->  Test -> SOLUTION: A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the rectangle is 63 square feet. Find the length of the rectangle. Feet =       Log On


   

Question 1056235: A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the rectangle is 63 square feet. Find the length of the rectangle.
Feet =
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is,
A=L%2AW=63
and
W=L-2
Substituting,
L%28L-2%29=63
L%5E2-2L-63=0
%28L-9%29%28L%2B7%29=0
Only one solution is positive,
L-9=0
L=9ft
So then,
W=9-2
W=7ft