SOLUTION: Can you please solve the following problem? Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 mile

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Question 1056233: Can you please solve the following problem?

Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 miles and one train goes 20 mph faster than the other, find the speed of the faster train.

Found 3 solutions by rfer, ikleyn, MathTherapy:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
300/2=150 per hr
x+x+20=150
2x=150-20
x=130/2
x=65 mph slow
x+20=85 mph fast

Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
.
Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them
is 300 miles and one train goes 20 mph faster than the other, find the speed of the faster train.
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1)  500 - 300 = 200 miles is decreasing the distance between two trains in 2 hours.

2) 200%2F2 = 100 miles per hr is the sum of their rates.

   x + (x+20) = 100

   2x = 100-20

   x = 80%2F2

   x = 40 mph slower

   x + 20 = 60 mph faster


Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

Can you please solve the following problem?

Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 miles and one train goes 20 mph faster than the other, find the speed of the faster train.
Let faster train’s speed be S
Then slower train’s speed = S – 20
At 1st they were 500 miles apart, but after 2 hours, they were 300 miles apart, which means that in 2 hours they covered 200 (500 – 300) miles
We then get the following DISTANCE equation: 2S + 2(S – 20) = 200
2S + 2S – 40 = 200
4S – 40 = 200
4S = 240
S, or speed of faster train = highlight_green%28matrix%281%2C4%2C+240%2F4%2C+or%2C+60%2C+mph%29%29