Question 1056223: Carmen was excited about the possibility of earning the "Mayfield Math Award." In order to do this she must have an average score of at least 92 in her first 5 tests. If her first 4 scores were 96, 90, 89, and 97, what is the lowest score Carmen could have on the 5th test and still earn the award?
F. 88
G. 89
H. 90
J. 91
K. 92
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! add 96, 90, 89, 97 and unknown x and divide by 5:
96+90+89+97+x/5 = 92
Do this:
Add all the numbers on the left.
Multiply both sides times 5. On the left, times 5/5 cancel each other and you are left with the sum of the numbers+x On the right you will have the product of 92 times 5.
Now subtract the sum on the left from the number on the right. You'll have the x by itself on the left and your answer on the right.
|
|
|
