SOLUTION: solve the equation sin(y+π/6)cos(y+π/6)= cos^2(y+π/6), for 0≤y≤6, giving your answers in terms of π.
Algebra ->
Finance
-> SOLUTION: solve the equation sin(y+π/6)cos(y+π/6)= cos^2(y+π/6), for 0≤y≤6, giving your answers in terms of π.
Log On
Question 1056163: solve the equation sin(y+π/6)cos(y+π/6)= cos^2(y+π/6), for 0≤y≤6, giving your answers in terms of π. Found 2 solutions by algebra hello, ikleyn:Answer by algebra hello(55) (Show Source):
You can put this solution on YOUR website! sin(y+π/6)cos(y+π/6)= cos^2(y+π/6)
sin(y+π/6)cos(y+π/6)/cos^2(y+π/6)=1
sin(y+π/6)/cos(y+π/6)=1
tan(y+π/6)=1
tan(y+π/6)=tanπ/4
(y+π/6)=π/4
y=π/4-π/6
y=π/12
sin(y+π/6)cos(y+π/6)= cos^2(y+π/6)
sin(y+π/6)cos(y+π/6)/cos^2(y+π/6)=1
sin(y+π/6)/cos(y+π/6)=1
tan(y+π/6)=1
tan(y+π/6)=tan(π/4)
(y+π/6) = , (since tan is periodical with the period )
y = π/4-π/6, y = (two solutions)
y = , y = (two solutions)
(
