SOLUTION: If cot(x)=-2 and cos(x)>0 find the exact value of cos(x/2)
I tried working it out based on where it would be on the graph from the cot(x) value and the Cos(x) being greater the
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-> SOLUTION: If cot(x)=-2 and cos(x)>0 find the exact value of cos(x/2)
I tried working it out based on where it would be on the graph from the cot(x) value and the Cos(x) being greater the
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Question 1056115: If cot(x)=-2 and cos(x)>0 find the exact value of cos(x/2)
I tried working it out based on where it would be on the graph from the cot(x) value and the Cos(x) being greater then 0
From there I tried to use conversions and just got lost. Any help to figure this out would be great. Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! First value tells you that and that means quadrant 2 or quadrant 4. Second part, means quadrant 1 or quadrant 4. The conclusion to make for what is common, is x is in quadrant 4.
You can draw a simple right triangle with radius endpoint in the quadrant 4 to help you further. Radius, or hypotenuse, is 1; horiZontal coordiante 2*k; vertical component or coordinate -1*k. You can also say, .
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