SOLUTION: Find all the angles between 0° and 360° inclusive which satisfy the equation cot(135°-2y)=-0.5

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Question 1056110: Find all the angles between 0° and 360° inclusive which satisfy the equation cot(135°-2y)=-0.5
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

cot%28%22135%B0%22-2y%29%22%22=%22%22-0.5

Cotangent is the reciprocal of the tangent:

1%2Ftan%28%22135%B0%22-2y%29%22%22=%22%22-0.5

Multiply both sides by tan(135°-2y):
 
1%22%22=%22%22-0.5tan%28%22135%B0%22-2y%29

Divide both sides by -0.5:

1%2F%28-0.5%29%22%22=%22%22tan%28%22135%B0%22-2y%29

Simplify left side:

-2%22%22=%22%22tan%28%22135%B0%22-2y%29

Use formula for tan(A-B):

-2%22%22=%22%22%28tan%28%22135%B0%22%29-tan%282y%29%29%2F%281%2Btan%28%22135%B0%22%29tan%282y%29%29

Use the fact that tan(135°) = -1, substituting:

-2%22%22=%22%22%28%28-1%29-tan%282y%29%29%2F%281%2B%28-1%29tan%282y%29%29

Simplify:

-2%22%22=%22%22%28-1-tan%282y%29%29%2F%281-tan%282y%29%29

Multiply both sides by 1-tan(2y):

-2%281-tan%282y%29%5E%22%22%29%22%22=%22%22-1-tan%282y%29

Distribute on the left:

-2%2B2tan%282y%29%22%22=%22%22-1-tan%282y%29

Add +2 to both sides:

2tan%282y%29%22%22=%22%221-tan%282y%29

Add + tan(2y) to both sides:

3tan%282y%29%22%22=%22%221

Divide both sides by 3:

tan%282y%29%22%22=%22%221%2F3

Use formula for tan(2θ):

2tan%5E%22%22%28y%29%2F%281-tan%5E2%28y%29%29%22%22=%22%221%2F3

Cross-multiply:

6tan%5E%22%22%28y%29%22%22=%22%221-tan%5E2%28y%29

Get 0 on the right:

tan%5E2%28y%29%2B6tan%5E%22%22%28y%29-1%22%22=%22%220

Use quadratic formula:

tan%28y%29+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A%28-1%29+%29%29%2F%282%2A1%29+

Simplify:

tan%28y%29+=+%28-6+%2B-+sqrt%2836%2B4%29%29%2F2+

tan%28y%29+=+%28-6+%2B-+sqrt%2840%29%29%2F2+

tan%28y%29+=+%28-6+%2B-+sqrt%284%2A10%29%29%2F2+

tan%28y%29+=+%28-6+%2B-+2sqrt%2810%29%29%2F2+

tan%28y%29+=+%282%28-3+%2B-+sqrt%2810%29%29%29%2F2+

tan%28y%29+=+%28cross%282%29%28-3+%2B-+sqrt%2810%29%29%29%2Fcross%282%29+

tan%28y%29+=+-3+%2B-+sqrt%2810%29+

Using the + :

tan%28y%29+=+-3+%2B+sqrt%2810%29+

tan%28y%29+=+0.1622776602

y+=+%229.217474413%B0%22  <-- 1st quadrant solution

Add 180° to get the 3rd quadrant solution:

y+=+%22189.217474413%B0%22  <-- 3rd quadrant solution

Using the - :

tan%28y%29+=+-3+-+sqrt%2810%29+

tan%28y%29+=+-6.1622776602

y+=+%22-80.78252559%B0%22  <-- 4th quadrant negative solution

which calculator always gives but which we cannot accept here
since it's not between 0° and 360°.

So we add 360° to get an equivalent positive 4th quadrant 
solution which is between 0° and 360:

y+=+%22279.217474413%B0%22  <-- 4th quadrant solution

Subtract 180° to get the 2nd quadrant solution:

y+=+%2299.217474413%B0%22  <-- 2nd quadrant solution

So there are 4 solutions between 0° and 360°.

Edwin