SOLUTION: Write the logarithmic expression as a sum or difference of logarithms. ln [(2x sqrt x^2+1)/(x+3)] all of x^2+1 is inside the square root So far I have ln(2) + ln(x) - ln(x+3

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Write the logarithmic expression as a sum or difference of logarithms. ln [(2x sqrt x^2+1)/(x+3)] all of x^2+1 is inside the square root So far I have ln(2) + ln(x) - ln(x+3      Log On


   



Question 1056096: Write the logarithmic expression as a sum or difference of logarithms.
ln [(2x sqrt x^2+1)/(x+3)]
all of x^2+1 is inside the square root
So far I have ln(2) + ln(x) - ln(x+3)
I think ln(x+3) stays the same, but that square root stuff is really confusing. thank you to whoever helps me out!

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Write the logarithmic expression as a sum or difference of logarithms.
ln [(2x sqrt x^2+1)/(x+3)]
all of x^2+1 is inside the square root
So far I have ln(2) + ln(x) - ln(x+3)
I think ln(x+3) stays the same, but that square root stuff is really confusing. thank you to whoever helps me out!
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ln [(2x sqrt x^2+1)/(x+3)] = ln%28%28%282x%29%2Asqrt%28x%5E2%2B1%29%29%2F%28x%2B3%29%29 = ln%282x%29 + ln%28sqrt%28x%5E2%2B1%29%29 - ln%28x%2B3%29 = ln%282%29 + ln(x) + %281%2F2%29%2Aln%28x%5E2%2B1%29 - ln%28x%2B3%29.


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Comment from student: Thank you so much for helping me out. The explanation to the logarithm math question
was answered by you extremely well. I understood everything (:
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My response: I am glad to hear it.

On logarithms, see a bunch of lessons
    - WHAT IS the logarithm,
    - Properties of the logarithm,
    - Change of Base Formula for logarithms,
    - Solving logarithmic equations,
    - Using logarithms to solve real world problems,  and
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".