Question 1056075: write an equation of the parabola with the given characteristic.
focus (0,-1) directrix: y = 1
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! Need to Know:
the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
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focus (0,-1) directrix: y = 1
the focus is (h,k + p)
k + p = -1 focus y = -1
k - p = 1 directrix: y = 1
k = 0, p = -1, a = -1/4
V(0,0)
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