SOLUTION: Write an equation of the parabola with the given characteristic. vertex: (0,0) directrix: y = -2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation of the parabola with the given characteristic. vertex: (0,0) directrix: y = -2      Log On


   

Question 1056074: Write an equation of the parabola with the given characteristic.
vertex: (0,0) directrix: y = -2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Need to Know:
the vertex form of a Parabola opening up(a>0) or down(a<0),
y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
|
vertex: (0,0) directrix: y = -2
directrix: y = -2
k - p = -2
0 - p = -2
p = 2, a = (1/8)
|
y=%281%2F8%29%28x%29%5E2+