SOLUTION: David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have
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Question 1056059: David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have?
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Value Eq:: 5n + 10d + 25q = 425 cents
Quantity:: q = n-3
Quantity:: d = 2n
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Divide through the 1st by 5
Substitute for "q" and for "d"
Solve for "n"::
n + 2d + 5q = 85
n + 2(2n) + 5(n-3) = 85
10n - 15 = 85
10n = 100
n = 10 (# of nickels)
d = 2n = 20 (# of dimes)
q = n-3 = 7 (# of quarters)
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Cheers,
Stan H.
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