SOLUTION: A cylindrical can holds
56 milliliters.
​(a) If the radius of the base is
doubled and the height​ halved, what is the new volume of the​ can?
​(b) If
Algebra ->
Volume
-> SOLUTION: A cylindrical can holds
56 milliliters.
​(a) If the radius of the base is
doubled and the height​ halved, what is the new volume of the​ can?
​(b) If
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Question 1055995: A cylindrical can holds
56 milliliters.
(a) If the radius of the base is
doubled and the height halved, what is the new volume of the can?
(b) If the radius of the base is halved and the height is
doubled, what is the new volume of the can? Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! r^2Pi*h = 56
a) 2(r^2Pi)1/2h = ?
b) 1/2(r^2Pi)*2h = ??
here you have the formulas laid out and ready for you to do your magic. Good luck, there are infinite combinations... unless you have information you didn't share with us.
