SOLUTION: Lois rode her bike to visit a friend. She traveled at 10mi/h. While she was there, it began to rain. Her friend drove her home in a car traveling at 25mi/h. Lois took 1.5h longer t

Algebra ->  Expressions-with-variables -> SOLUTION: Lois rode her bike to visit a friend. She traveled at 10mi/h. While she was there, it began to rain. Her friend drove her home in a car traveling at 25mi/h. Lois took 1.5h longer t      Log On


   

Question 105598: Lois rode her bike to visit a friend. She traveled at 10mi/h. While she was there, it began to rain. Her friend drove her home in a car traveling at 25mi/h. Lois took 1.5h longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house?
Answer by askmemath(368) About Me  (Show Source):
You can put this solution on YOUR website!
Since Lois travelled from home to her ftiend's house and back the distance travelled is same. Let this distance = D
Time taken on her cycle t_1=+D%2F10
Time taken in the car t_2=+D%2F25
Given that difference in time = 1.5 hours
i.e. +t_1+-+t_2+=+1.5
or %28D%2F10%29+-+%28D%2F25%29+=+1.5
Can you solve for D?
Once you find D, simply divide by 10 to find how long Lois took to reach her friend's house