SOLUTION: find two consecutive integers so that 3 times the lesser minus 2 times the greater is 43

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Question 1055942: find two consecutive integers so that 3 times the lesser minus 2 times the greater is 43
Answer by ikleyn(52852) About Me  (Show Source):
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find two consecutive integers so that 3 times the lesser minus 2 times the greater is 43
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3n - 2(n+1) = 43.

3n - 2n - 2 = 43,

n = 45.

The numbers are 45 and 46.