Question 1055927: From a bag with tickets marked 1 to 17 a ticket is drawn and replaced and a second drawing is done. what is the probability that
1) the first number drawn is even and the second is odd
2) the first number drawn is odd and the second is even
3) how are the results in 1) and 2) effected if the first ticket is not replaced.
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! 17 tickets
Odd: 1,3,5,7,9,11,13,15,17
Even: 2,4,6,8,10,12,14,16
ticket drawn with replacement
P(E, O) = (8/17)(9/17)
P(O, E) = (9/17)(8/17)
3) w/o replacement
P(E, O) = (8/17)(9/16)
P(O, E) = (9/17)(8/16)
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