SOLUTION: y= (x-4)2(2=to the second power)-1. I have to graph the parabola and four additional points, two on each side of the vertex. I have the vertex (4,1) but not sure how to get additio

Algebra ->  Coordinate-system -> SOLUTION: y= (x-4)2(2=to the second power)-1. I have to graph the parabola and four additional points, two on each side of the vertex. I have the vertex (4,1) but not sure how to get additio      Log On

Hi  

Need to know:

The vertex form of a Parabola opening up(a>0) or down(a<0), 

 where(h,k) is the vertex 

 

V(4, -1)

As to additional Point:  Plug x in to find y

x  y 

3  0

2  3

5  0

6  3