SOLUTION: Three brothers have ages that are consecutive odd integers. The sum of the age of the youngest brother and three times the oldest brother is five times five less than five times th

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Question 1055653: Three brothers have ages that are consecutive odd integers. The sum of the age of the youngest brother and three times the oldest brother is five times five less than five times the middle brother's age.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let the ages be N-2,N, and N%2B2.
N-2%2B3%28N%2B2%29=5%285N-5%29
N-2%2B3N%2B6=25N-25
4N%2B4=25N-25
-21N=-29
N=29%2F21
However the answer must be an integer.
Check your problem setup especially that last sentence.