SOLUTION: Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.

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Question 1055377: Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.
Answer by ikleyn(52790) About Me  (Show Source):
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Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.
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%28n%2B1%29%2F2+-+n%2F3 = 9,

Multiply by 6 both sides.

3(n+1) - 2n = 54,

3n + 3 - 2n = 54,

n = 54 - 3 = 51.

Answer.  51 and 52.

Check.   52%2F2+-+51%2F3 = 26 - 17 = 9.  Correct!