SOLUTION: Ref. Question 1055341; Just for info: Answers given with problem => x = .22 cu. yds. of cement, y = .44 cu. yds. of sand (y = 2x), z = .88 cu. yds. of gravel(z = 4x). My

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Ref. Question 1055341; Just for info: Answers given with problem => x = .22 cu. yds. of cement, y = .44 cu. yds. of sand (y = 2x), z = .88 cu. yds. of gravel(z = 4x). My       Log On

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Question 1055349: Ref. Question 1055341;
Just for info:
Answers given with problem => x = .22 cu. yds. of cement, y = .44 cu. yds. of sand (y = 2x), z = .88 cu. yds. of gravel(z = 4x).
My question: How did they obtain .22 for x ? Thanks again.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Can you repost the question?
Have you contacted the tutor that solved the problem originally?