SOLUTION: Find a polynomial function of degree 3 with the given numbers as zeros.
2,i, -i
This is what I tried:
F(x)=(x-2)(x+i)(x-i)
I factored(x+i)(x-i) and got x^2-1
After that I fa
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Find a polynomial function of degree 3 with the given numbers as zeros.
2,i, -i
This is what I tried:
F(x)=(x-2)(x+i)(x-i)
I factored(x+i)(x-i) and got x^2-1
After that I fa
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Question 1055344: Find a polynomial function of degree 3 with the given numbers as zeros.
2,i, -i
This is what I tried:
F(x)=(x-2)(x+i)(x-i)
I factored(x+i)(x-i) and got x^2-1
After that I factored (x^2-1)(x-2)
I got x^3-2x^2-x+2
I'm not exactly sure if I did that correctly.
You can put this solution on YOUR website! There are three real roots in the graph
You want (x^2+1), because (x+i)(x-i)=x^2-i^2=x^2-(-1)=x^2+1
Now expand (x^2+1)(x-2)
x^3-2x^2+x-2
