SOLUTION: Polygon K has 3 more sides and 2015 more diagonals than polygon N. How many sides does each of these polygons have?

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Question 1055215: Polygon K has 3 more sides and 2015 more diagonals than polygon N. How many sides does each of these polygons have?
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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Polygon K has 3 more sides and 2015 more diagonals than polygon N. How many sides does each of these polygons have?
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The key to the solution is this statement:

      The number of diagonals of the n-sided polygon is %28n%2A%28n-3%29%29%2F2.


It gives you an equation 

%28%28n%2B3%29%2An%29%2F2+-+%28n%2A%28n-3%29%29%2F2 = 2015.

Simplify. 

(n+3)*n - n*(n-3) = 2*2015,

n^2 + 3n - n^2 + 3n = 4030,

6n = 4030.

And since 4030%2F6 is not a whole number,

THE PROBLEM HAS NO SOLUTIONS.