SOLUTION: a function value and a qudrant are given, find the other five function values. give exact answers. cotθ = -3, quadrant IV sinθ = cosθ = tanθ = csc

Algebra ->  Trigonometry-basics -> SOLUTION: a function value and a qudrant are given, find the other five function values. give exact answers. cotθ = -3, quadrant IV sinθ = cosθ = tanθ = csc      Log On


   



Question 1055186: a function value and a qudrant are given, find the other five
function values. give exact answers.
cotθ = -3, quadrant IV
sinθ =
cosθ =
tanθ =
cscθ =
secθ =

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

We draw an angle in the 4th quadrant like below.  Since the cotangent is the
adjacent over the opposite, or x%2Fy, we make the given cotangent,-3, into a
fraction -3%2F1, but in quadrant IV, x goes right and y goes down, so the
numerator x is positive and the denominator y is negative, so we change the -3%2F1 to %28%22%22+%2B+3%29%2F%28-1%29 and make the numerator
+3 be the value of x and the denominator -1 be the value of y.

so we have:    
 
 


Now we need to know that 

the sine is the opposite over the hypotenuse or y/r, which is 
%28-1%29%2Fsqrt%2810%29%29 or -sqrt%2810%29%2F10. 

the cosine is the adjacent over the hypotenuse or x/r, which is 
3%2Fsqrt%2810%29%29 or 3sqrt%2810%29%2F10. 

the tangent is the opposite over the adjacent or y/x, which is 
%28-1%29%2F3 or -1%2F3. 

the secant is the hypotenuse over the adjacent or r/x, which is 
sqrt%2810%29%2F3%29. 

the cosecant is the hypotenuse over the opposite or r/y, which is 
sqrt%2810%29%2F%28-1%29%29 or -sqrt%2810%29. 

Edwin