SOLUTION: What is the minimum distance between the 2 parabolas: y = x^2+4 and x = y^2 ?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the minimum distance between the 2 parabolas: y = x^2+4 and x = y^2 ?      Log On


   



Question 1055178: What is the minimum distance between the 2 parabolas:
y = x^2+4 and x = y^2 ?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
OK, assume that the shortest distance line segment intersects the first curve at (a,a%5E2%2B4) and intersects the second curve at (b%5E2,b).
The slope of the tangent line of the first curve at point a would be 2a since dy%2Fdx=2x.
The slope of the tangent line of the second curve at point b would be 1%2F%282b%29 since dy%2Fdx=1%2F%282%2Asqrt%28x%29%29.
The slopes are equivalent which leads to the first equation,
2a=1%2F%282b%29
4ab=1
.
.
.
Now use the distance formula (actually use the distance squared to eliminate the square root) with the two points of intersection,
D%5E2=%28a-b%5E2%29%5E2%2B%28a%5E2%2B4-b%29%5E2
From the previous equation,
a=1%2F%284b%29
Substitute,
D%5E2=%281%2F%284b%29-b%5E2%29%5E2%2B%281%2F%2816b%29%2B4-b%29%5E2
Graphing and finding the minimum,
b=1.188
So then,
a=1%2F%284b%29
a=0.210438
.
.
.
.
.
.
.
So then the points are (0.210,4.044) and (1.188,1.411)
Using the distance formula,
D%5Bmin%5D=3.098
You could also have just used the graphed value when we minimized the distance squared,
D%5Bmin%5D%5E2=9.601
D%5Bmin%5D=3.098
.
.
.
.