SOLUTION: I am having a hard time solving this problem and I have know idea where to begin. I know I have to find the price of one chair. 1 table and 6 chairs cost $540. 1 table cost 3 t

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I am having a hard time solving this problem and I have know idea where to begin. I know I have to find the price of one chair. 1 table and 6 chairs cost $540. 1 table cost 3 t      Log On


   

Question 1055083: I am having a hard time solving this problem and I have know idea where to begin. I know I have to find the price of one chair.
1 table and 6 chairs cost $540. 1 table cost 3 time more than one chair. How much do six chairs cost?
thank you
Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
t = 3c
t+6c = 540 substitute for t:
3c+6c = 540
9c = 540
c = 60 this is the price of one chair. And the table:
60*3 = 180 this is the price of the table
-------------------------
check:
1 table . . . . . . . . . . 180
6 chairs at 60 each, 6*60 = 360
Total . . . . . . . . . . = 540 Correct

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I am having a hard time solving this problem and I have know idea where to begin. I know I have to find the price of one chair.
1 table and 6 chairs cost $540. 1 table cost 3 time more than one chair. How much do six chairs cost?
thank you
Let price of 1 table be T, and 1 chair, C

Then: T + 6C = 540 ------ eq (i)

Also, T = 4C (3 TIMES more than one chair means 4 TIMES the cost of 1 chair) ------ eq (ii)

3 TIMES AS MUCH means 3C