SOLUTION: find two consecutive even inergers whose sum is 98

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Question 105508: find two consecutive even inergers whose sum is 98
Answer by MathLover1(20850) About Me  (Show Source):
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x%2B%28x%2B2%29+=+98
2x+%2B2+=+98
2x+=+98+-2
2x+=+96 divide both sides by 2
x+=+96%2F2
x+=+48 first number is 48
x+%2B+2+=+50 second number is 50
48+%2B+50+=+98