SOLUTION: Separate 179 into two parts, such that the smaller part divides into the greater 5 times with a remainder of 23 .

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Question 1054955: Separate 179 into two parts, such that the smaller part divides into the greater 5 times with a remainder of 23 .
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x is smaller part
5x+23 is larger part
They add to 179
6x+23=179
6x=156
x=26
5x+23=153
They add to 179.