SOLUTION: (a) i. Show that if a + a -1 = 10/3 then 3a2 – 10a + 3 = 0
ii. Hence find { x : 3x + 3–x = 10/3}
in i.: a -1 is suppose to be a inverse
and 3a2 is actually 3a
Question 1054904: (a) i. Show that if a + a -1 = 10/3 then 3a2 – 10a + 3 = 0
ii. Hence find { x : 3x + 3–x = 10/3}
in i.: a -1 is suppose to be a inverse
and 3a2 is actually 3a squared
in ii.: 3x is actually 3 to the power x
and 3-x is actually 3 to the power negative x Answer by ikleyn(52817) (Show Source):
