Question 1054716: A private plane traveled from Seattle to a rugged wilderness, at an average speed of 88 mph. On the return trip, the average speed was 154 mph. If the total traveling time was 8 hours, how far is Seattle from the wilderness?
Found 3 solutions by Fombitz, Boreal, MathTherapy:
Answer by Fombitz(32388)   (Show Source):
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! v*t=distance
going there 88*t=distance
coming back, the time is (8-t) and the velocity 154, so the distance is 154(8-t)=
1232-154t. Set that equal to 88t, since the distance is the same
88t=1232-154t
242t=1232
t=5.091 hours
going over, the distance would be 448 miles
coming back, the time is 2.909 hours (add to 8 hours)*154mi/hr=447.99 miles
448 miles is the distance.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website!
A private plane traveled from Seattle to a rugged wilderness, at an average speed of 88 mph. On the return trip, the average speed was 154 mph. If the total traveling time was 8 hours, how far is Seattle from the wilderness?
Let distance be D
Then we get the following TIME equation: 
7D + 4D = 4,928 -------- Multiplying by LCD, 616
11D = 4,928
D, or distance = 
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