Question 1054693: Carson has $2.15 in nickels and dimes in a jar. He has 10 more nickels than dimes. How many nickels and dimes does he have? Found 2 solutions by addingup, ikleyn:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! n = d+10 we'll use this value for n next
0.05n+0.10d = 2.15
substitute for n
0.05(d+10)+0.10d = 2.15
0.05d+0.50+0.10 = 2.15
0.15d = 1.65
d = 1.65/0.15 this is how many dimes Carson has (use your calculator). Then
add 10 to the result, that's how many nickels he has.
You can put this solution on YOUR website! .
Carson has $2.15 in nickels and dimes in a jar. He has 10 more nickels than dimes. How many nickels and dimes does he have?
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Answer. 11 dimes and 21 nickels.
Solution (without using equations)
Take off these 10 nickels from the collection, for a moment (mentally).
Then you can group the remaining coins in sets consisting (one nickel, one dime) each,
and the total "value" of the remaining coins is 215 - 5*10 = 165 cents.
The worth of each group is 10+5 = 15 cents.
The number of thess groups is (obviously) = 11.
Does it tell you something?
