SOLUTION: A(-1,0) B(2,0) C(0,3) AP is an altitude of the triangle ABC and it cuts the y-axis at H. AP is perpendicular to BC. Find the general equation of AP.

Algebra ->  Graphs -> SOLUTION: A(-1,0) B(2,0) C(0,3) AP is an altitude of the triangle ABC and it cuts the y-axis at H. AP is perpendicular to BC. Find the general equation of AP.      Log On


   

Question 1054650: A(-1,0) B(2,0) C(0,3)
AP is an altitude of the triangle ABC and it cuts the y-axis at H. AP is perpendicular to BC. Find the general equation of AP.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find BC.
m%5BBC%5D=%283-0%29%2F%280-2%29=-3%2F2
So then,
m%5BBC%5D%2Am%5BAP%5D=-1
m%5BAP%5D=2%2F3
So then the equation for AP is (using the point slope form through (-1,0)),
y-0=%282%2F3%29%28x-%28-1%29%29
highlight%28y=%282%2F3%29x%2B2%2F3%29