SOLUTION: use the given information to find:
sin(s+t)
tan(s+t)
the quadrant of s+t
sin s= 1/7 QII
sin t= -6/7 QIV
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-> SOLUTION: use the given information to find:
sin(s+t)
tan(s+t)
the quadrant of s+t
sin s= 1/7 QII
sin t= -6/7 QIV
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Question 1054631: use the given information to find:
sin(s+t)
tan(s+t)
the quadrant of s+t
sin s= 1/7 QII
sin t= -6/7 QIV Answer by ikleyn(52787) (Show Source):
You can put this solution on YOUR website! .
use the given information to find:
sin(s+t)
tan(s+t)
the quadrant of s+t
sin s= 1/7 QII
sin t= -6/7 QIV
~~~~~~~~~~~~~~~~~~
Stap by step:
1. sin(s)= 1/7 QII ---> cos(s) = = = = .
The sign is "-" at sqrt since cosine is negative in QII.
2. sin(t)= -6/7 QIV ---> cos(t) = = = = .
The sign is "+" at sqrt since cosine is positive in QIV.
3. Now sin(s+t) = sin(s)*cos(t) + cos(s)*sin(t) = = .
4. Next cos(s+t) = cos(s)*cos(t) - sin(s)*sin(t) = = = .
5. Finally, tan(s+t) = = .
6. From (3), sin(s+t) is positive; from (4), cos(s+t) is negative. Hence, s+t lies in QII.