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Find three consecutive integers such that the sum of the second and the third is 30 greater than the first
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Let x be the smallest integer of the given three.
Then the integers are x, (x+1) and (x+2).
You are given that
(x+1) + (x+2) = x + 30.
Simplify:
2x + 3 = x + 30 ---> x = 30-3 = 27.
Answer. The integers are 27, 28 and 29.