SOLUTION: How would you solve the questions: How long will it take for $1400 dollars to grow to $11,900 at an interest rate of 2.3% if the interested is compounded quarterly? I am taking

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Question 1054609: How would you solve the questions:
How long will it take for $1400 dollars to grow to $11,900 at an interest rate of 2.3% if the interested is compounded quarterly? I am taking the amount and dividing it by the initial investment. My next step has been to plug the following into my TI 84 calculator:
log(1+.023)8.5
Can you tell me what I am doing wrong? I get 8.6 years but the correct answer should be 20.65 years.
Thank you

Found 3 solutions by josmiceli, addingup, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+A+=+P%2A%28+1+%2B+r%2Fn+%29%5E%28n%2At%29+
+A+=+11900+
+P+=+1400+
+r+=+.023+
+n+=+4+
Find +t+ in yrs
------------------------------
+11900+=+1400%2A%28+1+%2B+.023%2F4+%29%5E%28+4t+%29+
+%28+1+%2B+.023%2F4+%29%5E%284t%29+=+8.5+
+%28+1+%2B+.00575+%29%5E%284t%29+=+8.5+
+1.00575%5E%284t%29+=+8.5+
Take the log base 10 of both sides
+log%28+1.00575%5E%284t%29%29+=+log%28+8.5+%29+
+log%28+1.00575%5E4+%29+%2B+log%28+1.00575+%29%5Et%29+=+log%28+8.5+%29+
+4%2A+log%28+1.00575+%29+%2B+t%2A+log%28+1.00575+%29+=+log%28+8.5+%29+
+4%2A.00249+%2B+.00249t+=+.92942+
+.00249t+=+.92942+-+.00996+
+.00249t+=+.91946+
+t+=+369.25+
I get a huge number
----------------------
20.65 yrs doesn't seem to work
+1.00575%5E%284t%29+=+8.5+
+1.00575%5E82.6+=+8.5+
+1.6057+=+8.5+ ??
Unless I messed up at the start
Are you sure all the data is correct?

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
P =initial principal 1,400
n = number of times the interest is compounded per year (in your case 4)
F = future amount after time t 11,900
r = annual nominal interest rate 2.3%
t = number of years we'll find out
We need to use the following financial formula:
t =ln(F/p)/(ln(1+r/n)n)
t = ln(11,900/1,400)/(ln(1+(0.023/4))4)
t = (ln 8.5)/((ln 1.00575)*4) do the operations and you'll get 93.31
-------------------------------
check:
1,400(1+(0.023/4)^4*93.31 =
1,400(1.00575)^4*93.31
1,400(1.00575)^373.24 = 11,899.0155
As you see I lost a few cents in the rounding of the numbers, but the answer is correct.
:
John

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

How would you solve the questions:
How long will it take for $1400 dollars to grow to $11,900 at an interest rate of 2.3% if the interested is compounded quarterly? I am taking the amount and dividing it by the initial investment. My next step has been to plug the following into my TI 84 calculator:
log(1+.023)8.5
Can you tell me what I am doing wrong? I get 8.6 years but the correct answer should be 20.65 years.
Thank you
It CANNOT be 20.65 years. That's IMPOSSIBLE! It's just too short a time!
You must be either looking at the wrong answer or failed to include the correct figures.
A+=+P%281+%2B+i%2Fm%29%5E%28mt%29
%22%2411%2C900%22+=+%22%241%2C400%22%281+%2B+.023%2F4%29%5E%284t%29 ------ Substituting $11,900 for A, $1,400 for P, .023 for i, and 4 (quarterly) for m
%22%2411%2C900%22%2F%22%241%2C400%22+=+1.00575%5E%284t%29 ------ Dividing both sides by $1,400, and simplifying 1+%2B+.023%2F4
8.5+=+1.00575%5E%284t%29
4t+=+log+%281.00575%2C+8.5%29 ------- Converting to LOGARITHMIC form
4t+=+log+%288.5%29%2Flog+%281.00575%29 ------ Applying change of base