SOLUTION: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M.
She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in th
Algebra ->
Finance
-> SOLUTION: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M.
She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in th
Log On
Question 1054600: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M.
She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in the food court. She
left to return home at 2:15 P.M. Because it had started raining, she drove 10 mph slower than she
did that morning. Marge got home at 4:15 P.M. What is the distance between the two cities? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Her driving time to Shelbyville was
10:45 minus 9:00 = hrs
( I converted 45 min to hrs )
----------------------------------
Her driving time back to Springfield was
4:15 minus 2:15 = hrs
----------------------------------
Let = her speed in mi/hr
driving to Shelbyville = her speed driving back
to Springfield in mi/hr
----------------------------------
Let = the distance between
the two cities in miles
----------------------------------
Equation for drive to Shelbyville:
(1)
Equation for drive back to Springfield:
(2)
----------------------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2)
--------------------
(1)
(1)
(1)
the distance between the 2 cities is 140 mi
--------------------
check answer:
(2)
(2)
(2)
(2)
OK
