SOLUTION: find real numbers a and b such that the equation is true (a+3)+8bi=3-3i

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Question 1054562: find real numbers a and b such that the equation is true (a+3)+8bi=3-3i
Answer by ikleyn(52790) About Me  (Show Source):
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find real numbers a and b such that the equation is true (a+3)+8bi=3-3i
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Two complex numbers are equal if and only if 

   a)  their real parts are equal, AND
   b) their imaginary parts are equal

(by the definition).


In your case it gives TWO equalities

a + 3 =  3,   (1)   and
8b    = -3.   (2)

Then a = 0  and  b = -3%2F8.

Solved.