SOLUTION: The equation for the motion of an object with constant acceleration is d=vt+0.5at squared where d is distance traveled in ft., v is starting velocity in ft/s, a is acceleration in

Algebra ->  Expressions-with-variables -> SOLUTION: The equation for the motion of an object with constant acceleration is d=vt+0.5at squared where d is distance traveled in ft., v is starting velocity in ft/s, a is acceleration in      Log On


   



Question 1054559: The equation for the motion of an object with constant acceleration is d=vt+0.5at squared where d is distance traveled in ft., v is starting velocity in ft/s, a is acceleration in ft/s squared, and t is time in seconds. A racecar begins with a velocity of 200ft/s squared and accelerates at 100ft/s squared?
Write an expression for the distance the car travels after 1 second.
What is the GCF of the expression?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+d+=+v%2At+%2B+.5a%2At+%5E2+
+v+=+200+ ft/sec
+a+=+100+ ft/sec2
+t+=+1+ sec
+d+=+200t+%2B+.5%2A100t%5E2+
+d+=+200t+%2B+50t%5E2+
+d+=+200%2A1+%2B+50%2A1%5E2+
+d+=+200+%2B+50+
+d+=+250+ ft