SOLUTION: Let Z be a standard normal random variable. Use the calculator provided to determine the value of C such that P(0.94 \LE Z \LE c)=0.1534 \LE = Less than equal to Carry

Algebra ->  Probability-and-statistics -> SOLUTION: Let Z be a standard normal random variable. Use the calculator provided to determine the value of C such that P(0.94 \LE Z \LE c)=0.1534 \LE = Less than equal to Carry      Log On


   



Question 1054417: Let Z be a standard normal random variable. Use the calculator provided to determine the value of C such that
P(0.94 \LE Z \LE c)=0.1534
\LE = Less than equal to
Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places.
The answer I got was .83 but I don't think this is correct. Can someone please confirm?

Answer by Fombitz(32388) About Me  (Show Source):