SOLUTION: Please help me solve this.
Identify the zeros for this equation, (x2 + 9)(x-2)(x + 2i)(x-2i)
A.) 3, -3, 2, 2i, -2i
B.) 9i, -9i, 2, 2i, -2i
C.) 3i, -3i, 2, 2i, -2i
D.) 9i,
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-> SOLUTION: Please help me solve this.
Identify the zeros for this equation, (x2 + 9)(x-2)(x + 2i)(x-2i)
A.) 3, -3, 2, 2i, -2i
B.) 9i, -9i, 2, 2i, -2i
C.) 3i, -3i, 2, 2i, -2i
D.) 9i,
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Question 1054408: Please help me solve this.
Identify the zeros for this equation, (x2 + 9)(x-2)(x + 2i)(x-2i)
A.) 3, -3, 2, 2i, -2i
B.) 9i, -9i, 2, 2i, -2i
C.) 3i, -3i, 2, 2i, -2i
D.) 9i, -9i, 3i, -3i, 2
Thank you. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Please help me solve this.
Identify the zeros for this equation, (x2 + 9)(x-2)(x + 2i)(x-2i)
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That's not an equation. There's no equal sign.
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(x2 + 9)(x-2)(x + 2i)(x-2i) = 0 is an equation.
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Use ^ (Shift 6) for exponents.
(x^2 + 9)(x-2)(x + 2i)(x-2i) = 0
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x^2 + 9 = 0
x = ± 3i
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x-2 = 0
x = 2
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etc
