SOLUTION: I need help solving this polynomial problem please! It has a zero:3, with multiplicity 1 and a zero:2, with a multiplicity 3, It also is a 4th degree poly with the coefficient as o

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need help solving this polynomial problem please! It has a zero:3, with multiplicity 1 and a zero:2, with a multiplicity 3, It also is a 4th degree poly with the coefficient as o      Log On


   

Question 1054399: I need help solving this polynomial problem please! It has a zero:3, with multiplicity 1 and a zero:2, with a multiplicity 3, It also is a 4th degree poly with the coefficient as one. I have tried a few times and the last time I tried solving it I got x^4-9x^3-14x^2+20x+24
Thank you so much!
Found 2 solutions by Boreal, Alan3354:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
It is (x-2)^3(x-3)
the first is x^3-6x^2+12x-8
The polynomial is (x^3-6x^2+12x-8)(x-2)
x^4-9x^3+30x^2-44x+24); f(2)=16-72+120-88+24=0; f(3)=81-243+270-132+24=0
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E4-9x%5E3%2B30x%5E2-44x%2B24%29
graph%28300%2C300%2C1%2C3.5%2C-10%2C10%2Cx%5E4-9x%5E3%2B30x%5E2-44x%2B24%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I need help solving this polynomial problem please! It has a zero:3, with multiplicity 1 and a zero:2, with a multiplicity 3, It also is a 4th degree poly with the coefficient as one. I have tried a few times and the last time I tried solving it I got x^4-9x^3-14x^2+20x+24
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--> (x-3)*(x-2)^3
= (x-3)*(x^3 - 6x^2 + 12x - 8)
= x%5E4+-+9x%5E3+%2B+30x%5E2+-+44x+%2B+24