SOLUTION: Solve. {{{ log2(3-7x)=log2(6x^2) }}} Can someone be generous enough to help me? Please & thanks!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve. {{{ log2(3-7x)=log2(6x^2) }}} Can someone be generous enough to help me? Please & thanks!      Log On


   

Question 1054394: Solve.
+log2%283-7x%29=log2%286x%5E2%29+
Can someone be generous enough to help me? Please & thanks!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
+log2%283-7x%29=log2%286x%5E2%29+, both log2
6x^2 = 3-7x
6x^2 + 7x - 3 = 0
(3x-1)(2x +3) = 0
x = 1/3
0r
x = -3/2