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https://www.youtube.com/watch?v=pqeI94Jri1M
The number of paper cranes that Thomas has is 8 times that of Raymond.
So
T = 8R
If Thomas gives 28 paper cranes to Raymond,
then Thomas will have T-28 paper cranes,
and Raymond will have R+28
they will have the same number of paper cranes.
So T-28 = R+28
That gives us this system of two equations in
two unknowns:
Solve that by substituting 8R from the first equation
for T in the second equation:
8R-28 = R+28
7R = 56
R = 8
The substitute 8 for R in T=8R
T = 8(8)
T = 64
Let's check that so far:
The number of paper cranes that Thomas has, which is 64,
is 8 times that of Raymond, which is 8.
If Thomas gives 28 paper cranes to Raymond, then Thomas
will have only 64-28 or 36, and Raymond will have 8+28 or 36,
so they will have the same number of paper cranes.
So it is correct. But the question is:
How many paper cranes do they have altogether?
They have 8+64 or 72 paper cranes altogether.
Edwin
