SOLUTION: Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B,
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-> SOLUTION: Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B,
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Question 1054033: Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B, she will use half of the money brought.
Given that the price of each orange in brand B is $1 less than that in brand A, find the original amount that Mrs Parkson has. Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! x, price of one of brand A
y, price of one of brand B
h, amount of money Mrs. Parkson is holding before any purchase
BUY 12 of brand A, keep $96.
BUY 24 of brand B, keep dollars.
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This makes for a system of equations
and you can probably solve this without trouble.
You can put this solution on YOUR website!
Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B, she will use half of the money brought.
Given that the price of each orange in brand B is $1 less than that in brand A, find the original amount that Mrs Parkson has.
Let original amount she had be D
Then cost of 1 dozen Brand A oranges = D – 96, and cost of 1 Brand A orange is:
Cost of 2 dozen Brand B oranges = ½D, or , & cost of 1 Brand B orange =
We then get:
4(D – 96) = D + 48 ------- Multiplying by LCD, 48
4D – 384 = D + 48
4D – D = 48 + 384
3D = 432
D, or original amount she had was:
(