SOLUTION: The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation $1200. The daily revenue totals for the next 30 days will be monit

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Question 1053922: The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation $1200. The daily revenue totals for the next 30 days will be monitored. What is the probability that the mean daily revenue for the next 30 days will exceed $7500?
How can I solve this with a calculator?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
mean $7200 and standard deviation $1200.
n = 30, x̄ = mean daily revenue for the next 30 days
Need to Know: z+=blue+%28x-bar+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29
P(x̄ >7500) = 1- P(x̄ <= 7500) = 1- P(z <= %287500+-7200%29%2F+%281200%2Fsqrt%2830%29%29)
Use Calculator to find value of z
then use Calculator to find P( z <= that value) = normalcdf(-100, z-value)
-100 a place value