SOLUTION: In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs. A. 2004-04-01-04-00_files/i0140001.jpg B. 2004-04-01-04-00_files/i0140003.j

Algebra ->  Geometry-proofs -> SOLUTION: In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs. A. 2004-04-01-04-00_files/i0140001.jpg B. 2004-04-01-04-00_files/i0140003.j      Log On


   

Question 1053860: In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs.
A.
2004-04-01-04-00_files/i0140001.jpg
B.
2004-04-01-04-00_files/i0140003.jpg
C.
2004-04-01-04-00_files/i0140002.jpg
D.
2004-04-01-04-00_files/i0140004.jpg
Found 2 solutions by Alan3354, addingup:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs.
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The legs are equal, so
s^2 + s^2 = 11^2

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
This is a very special type of triangle that has a unique ratio. The two legs are the exact same length, and the hypotenuse is that length times the square root of 2. Therefore, the sides are equal to the hypotenuse divided by the square root of 2:
:
h/sqrt2 = side
11/sqrt2 = side
now we calculate the square root of 2 and we get 1.4142
11/1.4142 = 7.78 is the length of each side