SOLUTION: Solve for x if: 6cos^2 x=5 +sin x; 0`less/equal to x less/equal to 90`

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Question 1053684: Solve for x if:
6cos^2 x=5 +sin x; 0`less/equal to x less/equal to 90`
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x if:
6cos^2 x=5 +sin x; 0`less/equal to x less/equal to 90`
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6*cos^2(x) = 5 + sin(x) ; 0<= x <= 90
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6*(1-sin^2(x)) = 5 + sin(x)
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6 - 6sin^2(x) = 5 + sin(x)
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6sin^2(x) + sin(x) -1 = 0
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(3sin(x)-1)(2sin(x)+1) = 0
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(sin(x) = 1/3 or sin(x) = -1/2
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If sin(x) = 1/3
x = arcsin(1/3) = 19.47 degrees
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If sin(x) = -1/2 there is no solution in 0<= x <=90
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Cheers,
Stan H.
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